c^2+3c-18=

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Solution for c^2+3c-18= equation:


Simplifying
c2 + 3c + -18 = 0

Reorder the terms:
-18 + 3c + c2 = 0

Solving
-18 + 3c + c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-6 + -1c)(3 + -1c) = 0

Subproblem 1

Set the factor '(-6 + -1c)' equal to zero and attempt to solve: Simplifying -6 + -1c = 0 Solving -6 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '6' to each side of the equation. -6 + 6 + -1c = 0 + 6 Combine like terms: -6 + 6 = 0 0 + -1c = 0 + 6 -1c = 0 + 6 Combine like terms: 0 + 6 = 6 -1c = 6 Divide each side by '-1'. c = -6 Simplifying c = -6

Subproblem 2

Set the factor '(3 + -1c)' equal to zero and attempt to solve: Simplifying 3 + -1c = 0 Solving 3 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -1c = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -1c = 0 + -3 -1c = 0 + -3 Combine like terms: 0 + -3 = -3 -1c = -3 Divide each side by '-1'. c = 3 Simplifying c = 3

Solution

c = {-6, 3}

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